x^2+45x-350=0

Solution for x^2+45x-350=0 equation:

x^2+45x-350=0

a = 1; b = 45; c = -350;
Δ = b2-4ac
Δ = 452-4·1·(-350)
Δ = 3425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3425}=\sqrt{25*137}=\sqrt{25}*\sqrt{137}=5\sqrt{137}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-5\sqrt{137}}{2*1}=\frac{-45-5\sqrt{137}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+5\sqrt{137}}{2*1}=\frac{-45+5\sqrt{137}}{2}
$